代码如下

use serde::{Deserialize, Serialize};

#[derive(Serialize, Deserialize)]
struct Person {
    id: String,
    name: String,
}

#[derive(Serialize, Deserialize)]
struct Msg<'a> {
    id: String,
    person: &'a Person,
}

fn main() {
    let person = Person {
        id: "123".to_string(),
        name: "Alice".to_string(),
    };

    let msg = Msg {
        id: "456".to_string(),
        person: &person,
    };

    let msg_str = serde_json::to_string(&msg).unwrap();
    println!("Serialized Msg: {}", msg_str);
}

报错如下

error[E0277]: the trait bound `&'a Person: Deserialize<'_>` is not satisfied
    --> src/main.rs:2463:13
     |
2463 |     person: &'a Person,
     |             ^^^^^^^^^^ the trait `Deserialize<'_>` is not implemented for `&'a Person`
     |
note: required by a bound in `next_element`
    --> /home/alxps/.cargo/registry/src/index.crates.io-6f17d22bba15001f/serde-1.0.195/src/de/mod.rs:1726:12
     |
1724 |     fn next_element<T>(&mut self) -> Result<Option<T>, Self::Error>
     |        ------------ required by a bound in this associated function
1725 |     where
1726 |         T: Deserialize<'de>,
     |            ^^^^^^^^^^^^^^^^ required by this bound in `SeqAccess::next_element`
help: consider removing the leading `&`-reference
     |
2463 -     person: &'a Person,
2463 +     person: Person,
     |

我不想让msg有person所有权，也不想clone person，现在要自定义序列化实现trait，要怎么写？或者有没有其他方法